**Statement: The sum of voltage rise in any electrical circuit is equal to the sum of voltage drops in that circuit.***Consider an electrical source with a voltage source which connects with three resistors. R*

_{1}, R

_{2}and R

_{3}. The sum of voltage drops across these resistors is equal to the sum of the input voltage(voltage rise).

Here are a few examples of KVL which help you to learn it in a better way:

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Example 1: A 15 V input source powers three resistors, having a series current of 2 mA flowing through them. Find the voltage across R_{3}.

Solution:

Step 1: Using Ohm's law find the voltage drop across the first resistor.

V = IR = 2 mA* 2 kohm = 4 V

Step 2: Applying KVL:

V_rise = V_drop

V_rise = V_drop

15 V = 4 V + 5 V + V_R_3

V_R_3 = 15 V - 5 V - 4 V = 6 V

### Example 2: A 20 V source powers three series resistors. The wattage rating of the first one being 30 watts having a current of 3 A flowing through it. The second resistance has all parameters unknown. Whereas, the third one has a voltage drop of 5 V across it. Find all unknown voltages in the circuit.

Step 1: Using formulas P = VI, or V = P/I = 30 watt/3 A = 10 V

Step 2: Using KVL;

V_rise = V_drop;

20 V = 10 V + V_R_2 + 5 V

or V_R_2 = 15 V

I think in the last line VR2=should be 5V not 15V

ReplyDeleteThe first example schematic shows a 2A current, in the calculation 2mA is used.

ReplyDeleteIn Example:2 VR2=5v not 15v

ReplyDelete