A load withdraws 60 kW at a PF 0.8, Calculate the Required Reactive Power to Improve it to 0.9

Statement: An electrical load withdraws 60 kW at PF of 0.8. It is desired to improve the PF from 0.8 to 0.9. Find the reactive power which should be provided.

a-load-withdraws-60-kw-at-a-pf-0.8-calculate-the-required-reactive-power-to-improve-it-to-0.9
Solution: Here Cos 𝜽 = 0.8, or 𝜽 = 36.86,
From Power Factor triangle:
At 0.8 the reactive power is: Q = tan (36.86) * 60 kW = 44.98 kvar

At PF of 0.9, Cos 𝜽 = 0.9, or 𝜽 = 25.84
& Q = tan (25.84) * 60 kW = 29.056 kvar

The reactive power which is supplied by capacitor = 44.98 - 29.056 = 15.9

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