We previously studied the application of voltage divider rule with various examples. In this post, you'll learn the method to apply voltage divider on three series resistors.

Statement: Three resistors of 22 Ω, 44 Ω, and 66 Ω are connected in a series configuration. The input voltage source is a 12 V battery. Apply the voltage divider rule to find the current across three resistors. Mention the observations.

Solution: Let's rewrite the general voltage divider formula:

In the present case we have three resistors. So

VStatement: Three resistors of 22 Ω, 44 Ω, and 66 Ω are connected in a series configuration. The input voltage source is a 12 V battery. Apply the voltage divider rule to find the current across three resistors. Mention the observations.

Solution: Let's rewrite the general voltage divider formula:

In the present case we have three resistors. So

_{x}. = [R

_{x}/ {R

_{1}+ R

_{2}+ R

_{3}} ] *V

_{in}

asdas

For R

_{1 }> V

_{1}= [R

_{1}/ {R

_{1}+ R

_{2}+ R

_{3}} ] *V

_{in}= [22 Ω/ {22 Ω + 44 Ω + 66 Ω} ] * 12 V = 2 V

For R

_{2 }> V

_{2}= [R

_{2}/ {R

_{1}+ R

_{2}+ R

_{3}} ] *V

_{in}= [44 Ω/ {22 Ω + 44 Ω + 66 Ω} ] * 12 V = 4 V

For R

_{3 }> V

_{3}= [R

_{3}/ {R

_{1}+ R

_{2}+ R

_{3}} ] *V

_{in}= [66 Ω/ {22 Ω + 44 Ω + 66 Ω} ] * 12 V = 6 V

After solving this problem we observe that the higher the resistance, the more voltage is dropped across it.

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