A current source of 100 mA powers two parallel resistors, the first resistor is of 30 Ω and it receives 60 mA current, Find the value of the second resistor.
Solution: R_1 dissipates the 60 mA, the remaining 40 mA current will pass through R_2.
From the Ohm's law, the voltage across 30-ohm resistor is 1.8 V.
R_1 and R_2 join in parallel and both have the same voltage across them.
V_R_2 = 1.8 V,
Using the Ohm's law R2 = V_R2/I_R2 = 1.8 V / 40 mA
R2 = 45 ohm
So 45 ohm is the right answer.
R2 = 45 ohm
So 45 ohm is the right answer.
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