# Basics of Electrical Engineering

Learn the basics of Electrical Engineering.

We previously studied the application of voltage divider rule with various examples. In this post, you'll learn the method to apply voltage divider on three series resistors.

Statement: Three resistors of 22 Ω, 44 Ω, and 66 Ω are connected in a series configuration. The input voltage source is a 12 V battery. Apply the voltage divider rule to find the current across three resistors. Mention the observations.
Solution: Let's rewrite the general voltage divider formula:
In the present case we have three resistors. So

Vx. = [Rx/ {R1 + R2 + R3} ] *Vin
asdas
For R> V1 = [R1/ {R1 + R2 + R3} ] *Vin = [22 Ω/ {22 Ω + 44 Ω + 66 Ω} ] * 12 V = 2 V
For R> V2 = [R2/ {R1 + R2 + R3} ] *Vin = [44 Ω/ {22 Ω + 44 Ω + 66 Ω} ] * 12 V = 4 V
For R> V3 = [R3/ {R1 + R2 + R3} ] *Vin = [66 Ω/ {22 Ω + 44 Ω + 66 Ω} ] * 12 V = 6 V

After solving this problem we observe that the higher the resistance, the more voltage is dropped across it.