In our previous tutorial, we learned the application of Branch current analysis in a 2 loop circuit with an example.
In this example, a network having three loops is solved using branch current analysis.

In this example, a network having three loops is solved using branch current analysis.

Step 1: Let's first label the circuit:
Step 2: Apply the Kirchhoff's voltage law in the loop between I2 and I3.
5 V = 2 I2 - 2 I3 ... (1)
Step 3: Apply KVL in the right loop.
1 V = 2 I3 + 2 I4 ... (2)
Step 4: Apply Kirchhoff's current law at node a.
1 A + I2 + I3 = I4... (3)
Solving the three equations we obtain our final answers:
I2 = 1.5 A
I3 = - 1 A
I4 = 1.5 A
Negative sign with current I3 indicates that actual current flow is opposite to our assumed direction of the current.
Step 3: Apply KVL in the right loop.
1 V = 2 I3 + 2 I4 ... (2)
Step 4: Apply Kirchhoff's current law at node a.
1 A + I2 + I3 = I4... (3)
Solving the three equations we obtain our final answers:
I2 = 1.5 A
I3 = - 1 A
I4 = 1.5 A
Negative sign with current I3 indicates that actual current flow is opposite to our assumed direction of the current.
How to solution of current source problem?
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